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bwkaz said
Sure, just factor it.
Oh, wait... not all polynomials factor...
They might not factor but you could do it this way by calculating all of the roots to the desired precision, however this isn't the best way to solve the problem
http://mathworld.wolfram.com/Fundame...ofAlgebra.html
bwakz, cfaun5, no arithmetic is allowed anywhere in the function, pretend your writing a multiprecision library and you want it to execute as fast as possible.
Last edited by grady; 08-22-2003 at 12:50 AM.
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